Permutations & Combinations

Report
Question

Please briefly explain why you feel this question should be reported .

Report
Cancel

If 6Pr = 360 and If 6Cr = 15, find r ?

solved 0
Permutations & Combinations Admin 3 years 6 Answers 1773 views 0

Answers ( 6 )

  1. Please briefly explain why you feel this answer should be reported .

    Report
    Cancel

    r=4

  2. Please briefly explain why you feel this answer should be reported .

    Report
    Cancel

    6!÷(n-r)!)÷(6!÷(r!)(n-r)!=360÷15 =r!=24 ans-4

  3. Please briefly explain why you feel this answer should be reported .

    Report
    Cancel

    6!/(6-r)!=24×6!/r!×(6-r)!
    Simplifying we get r=4

  4. Please briefly explain why you feel this answer should be reported .

    Report
    Cancel

    r!=24 then r=4.

  5. Please briefly explain why you feel this answer should be reported .

    Report
    Cancel

    nPr = nCr×r!
    6Pr = 15 *r!
    360 =15 *r!
    r! =360 /15 =24
    r! = 4*3*2*1
    => r! =4!
    Therefore, r = 4.

    Best answer
  6. Renuka

    Please briefly explain why you feel this answer should be reported .

    Report
    Cancel

    n!/(n-r)!=360 n!/ r!(n-r)!=15

    r!=24
    =4.3.2.1

    So ans= 4.

Leave an answer

Browse

Captcha Click on image to update the captcha .