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## Calendar

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The calendar for the year 1993 will be same for the year?

A) 2004

B) 1992

C) 1999

D) 2003

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## Answers ( 10 )

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An ordinary year has 1 odd day.

While a leap year has 2 odd days.

Let us assume

01-01-1993 as monday

Then,

01-01-1994 will be Tuesday bcs 1993 is an ordinary year which has 1 odd day

01-01-1995 will be Wednesday

01-01-1996 will be Thursday

01-01-1997 will be Saturday bcs 1996 is a leap year and it has 2 odd days

01-01-1998 will be Sunday

01-01-1999 will be Monday

Thus calendar 1993 will be repeated in 1999.

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1999

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1993,first divide by 4 in last 2 digits ie 93/4=23 remainder 1 means we have to add 11 so answer is 1993+11=2004

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Sir, if the remainder is either 2 or 3, then is the same procedure repeated as for 1???

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Correct answer is 1999.

Calculate the odd days from 1993. You get 7 days till 1998. So next year will have same calendar.

Year 1992 & 2004 is leap year. So you can directly eliminate those two options.

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Atfirst divide a year by 4. if any remainder is come it is non leap year. no remainder is come it is leap year.

If leap year comes (ex monday goes to wednesday in next year)

if non leap year comes ( ex monday goes to tuesday in next year)

if consider 1993 starts on monday

1994 – tuesday (leap year) 1995 – thursday 1996 – friday 1997 – saturday 1998 – sunday 1999 – tuesday

2000 – wednesday 2001 – thursday 2002 – friday (leap year) 2003 – sunday 2004 – monday

ans : 2004

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Odd days in the sense?

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Odd Days — Number of days more than the complete weeks are called odd days.

For Ordinary Year = 365 days = 52 weeks + 1 day (i.e 1 odd day)

For Leap Year = 366 days = 52 weeks + 2 days (i.e 2 odd days)

For more details, refer below link.

https://prep.placementseason.com/reasoning/calendars/

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A option is correct.

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If it is wrong pls let me know

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